7.6Math Journey Lab
Mission progress0 of 10
Chapter 7 · Circular-track travel

Switching Routes and Connected Loop Networks

变轨与相连环路

A switch may change before a traveler reaches it, and two travelers may share only part of a network. Learn to track the current route, the selected route, the next junction, and every encounter.

Track the state. Change routes only at a junction. Count meetings only on shared paths.
Grade 5 enrichment45–60 minutesEvent timelinesConnected loops
Mission 1

A route selector is not the same as the route being traveled

On a network, the switch can select a new loop while the train is still far from the junction. The train changes routes only when it actually reaches the junction.

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Four pieces of state

At any moment, record:

selected route · actual route · current position · return count

The selector tells us which route is ready. The actual route tells us where the train is moving now.

The junction rule

A track switch cannot pull a moving train sideways from the middle of a loop.

route changes only when the train reaches junction A

So every route-change problem is an event problem, not just a speed problem.

Simplified two-loop model sharing junction Ainteractive model

The dashed route is selected. The solid route is the one currently being traveled.

Check the rule

Mission 2

Convert loop length into lap time

For Missions 2–5, the train moves continuously at a constant 10 metres per minute, without waiting at the junction. One loop is 3 metres long and the other is 1.5 metres long.

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Lap-time machine

3 m
1.5 m
10 m/min
18large-loop seconds
9small-loop seconds
3⅓large laps per min
6⅔small laps per min

original values

3 ÷ 10 minute = 0.3 minute = 18 seconds
1.5 ÷ 10 minute = 0.15 minute = 9 seconds

Converting to seconds makes the one-minute switch schedule much easier to track.

Calculate the two lap times

Use lengths 3 m and 1.5 m and speed 10 m/min, regardless of the machine controls. Later train questions use these same fixed values.

Mission 3

Follow the train through the first route change

The train leaves junction A at time 0 on the selected large loop. The selector alternates every 60 seconds: small at 60 s, large at 120 s. At each arrival at A, the train immediately follows the selected loop. Time 0 is not a return. At 60 s the train is still between junction visits.

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60 s
Smallselected route
Largeactual route
3returns to A
72 snext arrival at A
Train state from 0 to 72 secondsoriginal example

Move the slider across the selector change at 60 seconds and the junction arrival at 72 seconds.

At 60 seconds: the train has completed three 18-second large laps, using 54 seconds. It is already 6 seconds into the next large lap. The remaining time to A is 18−6=12 seconds, so the actual switch occurs at 72 seconds.

Build the first event

Mission 4

Count the tenth return to A

The train enters the small loop at 72 seconds. It returns every 9 seconds. At 120 seconds the selector changes again, but the train must finish its current small lap.

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120 s
Largeselected route
Smallactual route
9returns to A
126 snext arrival at A

Returns on the large loop

The train returns at:

18, 36, 54, 72 seconds

The return at 72 seconds is return number 4.

Returns on the small loop

After switching at 72 seconds, it returns at:

81, 90, 99, 108, 117, 126 seconds

The return at 126 seconds is return number 10.

Complete the count

Mission 5

Build an event-driven route-state table

A reliable solution records what the selector says and what the train is actually doing at each important time.

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60 s
TimeSelectorActual routeWhat happens
0 sLargeLargeDepart A; start is not counted as a return.
60 sSmallLargeSelector changes while the train is between returns.
72 sSmallSmallReturn 4; train now enters the selected small loop.
120 sLargeSmallSelector changes, but the train is 3 seconds into a small lap.
126 sLargeLargeReturn 10; train now enters the large loop.

Read the state, not just the timer

Mission 6

Map two figure-eight routes on three connected loops

Each circle has circumference 210 cm. Caterpillar A moves at a constant 20 cm/min and B at 15 cm/min, starting simultaneously at the marked outermost points. A first follows the lower half of loop 1 to C, then one full clockwise lap of loop 2. B first follows the lower half of loop 3 to D, then one full counterclockwise lap of loop 2. Each then returns to its own outer loop and continues the figure-eight route without stopping. Only loop 2 and its junctions are shared.

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Three-loop connected networkguided practice problem

A starts at the far-left point A. B starts at the far-right point B. They can meet only while both occupy the shared middle loop or one of its junctions.

A’s route

loop 1 + loop 2 = 210+210=420 cm

A reaches junction C after half of loop 1:

105÷20=5.25 minutes

B’s route

loop 3 + loop 2 = 210+210=420 cm

B reaches junction D after half of loop 3:

105÷15=7 minutes

Build the route map

Mission 7

Find the first meeting on the shared loop

At 7 minutes, B has just reached D. A has already been on the middle loop for 1.75 minutes.

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7.00 min
35A: clockwise cm from C
105B: clockwise coordinate
70gap to first meeting
0meetings so far
Shared-loop meeting simulator7 to 9 minutes

The lower number line unwraps the 210-cm middle circle from C back to C.

At 7 minutes: A has traveled 20×7=140 cm. The first 105 cm reached C, so A is 35 cm into the middle loop. D is 105 cm from C, leaving a 70-cm approaching gap.

Calculate the first meeting

Mission 8

Find the second meeting before either traveler leaves the shared loop

After the first meeting, the next meeting needs one full relative lap of the shared 210-cm circle.

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15.00 min
195A coordinate on loop 2
195B coordinate on loop 2
0gap to next meeting
2meetings so far
Second-meeting simulatororiginal guided practice

A stays on loop 2 until 15.75 minutes. B stays there until 21 minutes, so the second meeting at 15 minutes is valid.

Time between meetings

210÷(20+15)=6 minutes

First meeting at 9 minutes:

9+6=15 minutes

Total distance since time 0

20×15=300 cm

By the second meeting, caterpillar A has crawled 300 centimetres.

Complete the second meeting

Mission 9

Switching-route and loop-network workshop

Solve at least six of the eight questions. These combine lap times, delayed route changes, shared-loop entry, and repeated meetings.

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1. A 4-m loop is traveled at 12 m/min. One lap takes how many seconds?

2. A 2-m loop at the same speed takes how many seconds?

3. A train is on the 20-second loop. The selector changes at 45 seconds. The train last passed the junction at 40 seconds. At what time can it actually switch?

4. In the fixed train scenario from Missions 2–5, which route is the train actually traveling at 60 seconds? Enter large or small.

5. At what second does the train in Missions 2–5 return to A for the tenth time?

6. Two circles of circumference 210 cm make one figure-eight route. What is one full route length?

7. In the three-loop problem, at what minute do the caterpillars first meet?

8. How far has caterpillar A crawled by the second meeting?

Mission 10

Exit ticket

Check the five answers, then compare any uncertain steps in worked review. The optional reflection is not automatically graded.

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Certificate of mastery

Route-Network State Navigator

This certifies that the learner can track route selectors, actual routes, junction events, figure-eight paths, and repeated meetings on connected loop networks.

Teaching notes

The train investigation is based on Chapter 7, Example 4, and the three-loop caterpillar investigation is based on Guided Practice 4.

The worked example train returns to A for the tenth time after 126 seconds, or 2.1 minutes. In the three-loop problem, the caterpillars meet at 9 minutes and 15 minutes; by the second meeting, caterpillar A has traveled 300 cm.