21.1Math Education • Chapter 21
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Chapter 21 • Digit Sums

Locate Digits in Concatenated Number Strings

第21讲 数字和 · Lesson 21.1

Turn the endless-looking string 123456789101112… into manageable one-digit, two-digit, and three-digit blocks. Then locate distant positions and add only the digits you actually need.

Find the block → Find the numeral → Find the digit
original pages 121–12210 missionsInteractive locatorAutosaves locally
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Your toolkit: s(n) means the sum of the decimal digits of n. For example, s(203)=2+0+3=5. Try each checkpoint yourself, then open its on-page hint if you get stuck. No lesson or external chat is needed.
Mission 1

Read the counting string correctly

Write 1,2,3,… starting with 1, and number the written digits starting at position 1. The symbols are written without commas or spaces. A number’s place in the counting list and a digit’s position in the written string are different ideas.

Not complete

Build the beginning

Number index

The 12th positive whole number is:

12

Digit position

The 12th written digit in 123456789101112… is:

1

Positions 10–13 are the digits of 10 and 11.

Common mistake: the 207th digit is not the number 207. It is one symbol somewhere inside the concatenated string.

Checkpoint

Need a hint for Mission 1?

A numeral is the written form of a number; a position counts one written digit. Count 10 as two positions.

Check your method

The first nine positions are1–9. Positions10,11 hold10; positions12,13 hold11. 10;12;digit1;written digit positions.

Before using the locator

Predict the first digit after position 189. The numbers through 99 use 189 positions, so position 190 starts 100. For a position inside the three-digit block, subtract 1 before dividing by 3: a remainder of 0 means the first digit, 1 the second, and 2 the third.

Mission 2

Build digit-width blocks

Every numeral inside one block has the same number of digits. Count the numerals, then multiply by the width.

Not complete
One-digit block

1 through 9

9 × 1 = 9

Positions 1–9.

Two-digit block

10 through 99

90 × 2 = 180

Positions 10–189.

Three-digit block

100 through 999

900 × 3 = 2,700

Begins at position 190.

9 + 180 = 189 positions through 99
WidthNumeralsDigits in blockCumulative end

Checkpoint

Need a hint for Mission 2?

There are 90 two-digit numbers. Multiply the number of numerals by their width.

Check your method

There are9 one-digit and90 two-digit numerals. They use9+180=189 positions. 9;180;189;first position of100 is190.

Mission 3

Use a general Nth-digit locator

Subtract complete blocks until the target lies inside one width. Then divide by that width to locate the numeral and the digit inside it.

Not complete
Requested digit5

The gold box is the target. Blue boxes mark the first digit of a numeral.

Independent locator: position 250

Need a hint for Mission 3?

Subtract 189. Use (remaining − 1) ÷ 3: the quotient counts whole numerals before the target; the remainder chooses its digit.

Check your method

250−189=61. Subtract1:60÷3=20 remainder0, so the target is the first digit of100+20=120. 61;120;place1 from the left;digit1.

Mission 4

Worked example: locate position 207

The worked example first determines exactly which numeral contributes the 207th digit.

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Example 1

Complete practice problem

Write the positive integers consecutively as

1234567891011121314…

Find the sum of the digits in positions 1 through 207.

1. Remove complete blocks

207 − 189 = 18

2. Count three-digit numerals

18 ÷ 3 = 6

3. Find the sixth one

100 + 6 − 1 = 105

4. Choose its last digit

105 → 5
Because 18 is exactly divisible by 3, position 207 is the final digit of the sixth three-digit numeral.

Rebuild the worked example location

Need a hint for Mission 4?

After the first 189 digits, group the remaining digits in threes. An exact multiple ends at the last digit of a numeral.

Check your method

207−189=18=6×3. The sixth three-digit numeral is100+6−1=105. 18;six complete numerals;105;last digit5.

Mission 5

Pair 00 through 99 to total 900

The worked example pairs complementary two-digit displays. Every pair has combined digit sum 18.

Not complete

Choose a pair

The display 00 is only a visual aid. The number 0 contributes digit sum 0.

00
+
99
0 + 0 + 9 + 9 = 18
Numbers from 0 through 99100
Complement pairs50
Digit sum per pair18
Total digit sum900
50 × 18 = 900

Checkpoint

Need a hint for Mission 5?

Write each value with two places, including 00. Pair each digit with its complement to 9.

Check your method

Each pair has digit sum18 and uses two of the100 displays. 50 pairs;18;900;no, adding s(0)=0 changes nothing.

Mission 6

Finish the worked example sum through position 207

The target position ends exactly at 105, so add the full digit sums of 100 through 105 to the 0–99 total.

Not complete

Digits from 100 through 105

1+2+3+4+5+6 = 21

original total

900 + 21 = 921

The sum of the first 207 written digits is:

921

General prefix-digit-sum laboratory

Checkpoint

Need a hint for Mission 6?

Add the complete 00–99 block first, then the digit sums of 100 through the endpoint.

Check your method

s(100) through s(105) are1,2,3,4,5,6. Their sum21 joins the first-block total900. 21;921;last complete numeral105;yes.

Mission 7

Sum digit sums over a whole-number range

The notation s(n) means “sum the digits of n.” This is related to the string, but the endpoint is a whole numeral rather than a written position.

Not complete

Definition

s(203) = 2+0+3 = 5

Then s(1)+s(2)+⋯+s(M) adds the digit sum of every whole number from 1 through M.

General range digit-sum laboratory

Do not confuse the two laboratories: “first 203 written digits” and “all digit sums from 1 through 203” are different totals.

Checkpoint

Need a hint for Mission 7?

s(n) means the sum of the digits of n, not the sum of all numbers up to n.

Check your method

s(203)=5. From100–109 the digit sums total55;110–119 total65;120 contributes3. 5;900;900+55+65+3=1023;no boundary is required.

Mission 8

Guided practice: add s(1) through s(203)

Split the range into complete decimal blocks, then handle the short tail.

Not complete
Guided Practice 1

Extra practice

Find the sum of the digit sums of all positive integers from 1 through 203.

1 through 99complete two-digit display blockknown total900
100 through 199100 hundreds digitslast two positions repeat 00–99100+900=1000
200 through 203sums 2,3,4,5short tail14
900+1000+14=1914

Complete the worked example practice

Need a hint for Mission 8?

Every number through 203 is included in full. Split into 1–99, 100–199 and 200–203.

Check your method

100–199 contributes100 hundreds digits plus900 in the last two places. 200–203 contributes2+3+4+5=14. 1000;14;1914;100 numbers.

Try a new problem before the workshop

Locate position 192 in 123456789101112… and find the sum of the first 192 digits.

Compare your reasoning after trying

Positions 1–189 end at 99. The next three digits are 100, so position 192 is 0 and the sum is 900+1=901.

Mission 9

Independent workshop

Use the string 123456789101112… formed from all positive whole numbers, with positions counted from 1. Here s(n) means the sum of the digits of the complete numeral n. Correct all eight answers to complete the workshop.

Not complete
0 / 8
Need a hint for Mission 9?

Choose the matching method from this lesson. Write one intermediate step and check endpoints, digit restrictions, or carries before checking your answers.

Check your method

Position1000 is the first digit of370. The first15 digits end at the last digit of12; the first50 end at the first digit of30. 0;1;120;3;51;168;1023;1914.

Mission 10

Objective exit ticket

Answer all five correctly and complete the other nine missions to unlock the certificate.

Not complete
0 / 5

Optional reflection — not automatically graded

21.1

Concatenated-String Digit Navigator

This certifies that Student completed all ten missions and can locate distant written digits and sum structured digit ranges.

Chapter 21 • Digit Sums

Need a hint for Mission 10?

Choose the matching method from this lesson. Write one intermediate step and check endpoints, digit restrictions, or carries before checking your answers.

Check your method

Position207 ends105. Position195 ends101, so its digit is1. 9;189;5;921;1.