20.5Square Roots, Gaps & Shifts
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Chapter 20 • Perfect Squares

Work Backward with Square Roots, Gaps, and Shifts

第20讲 完全平方数 · Lesson 20.5

Turn a square clue into a root, factor the gap between two squares, and count every permitted shift without testing numbers one by one.

Root first. Factor the gap. Count the whole range.
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Mission 1

Build the square staircase

Growing an n × n square into an (n+1) × (n+1) square adds one row and one column. That makes every consecutive-square gap visible.

Not complete

The gap formula

(n+1)² − n² = 2n + 1

The new top row has n+1 cells. The new side column has n more cells. Together they add:

(n+1) + n = 2n+1
Consecutive perfect squares always differ by an odd number.

Adjust the lower root

49 new cellsnew row: n+1
48² = 2304
48new column: n

Checkpoint

Use the two printed gaps below, even if the diagram shows a different root.

Need a hint? Start here

The new border has n+1 cells in one row and n more in one column.

For the two printed gaps, n=48 and n=24. 97;49;odd.

Mission 2

Work backward from a square year

A story can hide both the square root and a subtraction. First find the only square year that fits the stated century.

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Exercise 3

original problem

An older brother says: “In the year of the twenty-first century, I will be exactly x years old.” In what year was he born?

Search the century by roots

For this lesson, the twenty-first century means the calendar years 2001 through 2100.

Then subtract the age

Square year
45² = 2025
Age that year
45
Birth year
2025 − 45 = 1980
original convention: this is a calendar-year subtraction. Birthdays within the year are not considered.
The worked example’s three-generation age problem also needs ordinary human-age bounds; that modeling issue was handled in Lesson 20.2.

Checkpoint

Answer the original 2001–2100 story, not an out-of-century slider example.

Need a hint? Start here

Find the square year within the stated century, then subtract the age, which is its root.

44²=1936,45²=2025,46²=2116. Subtract age45 from year2025. 2025;45;birth year1980.

Mission 3

Factor the gap between two squares

When two numbers are both squares, their difference factors into the difference and sum of their roots.

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Exercise 10

original problem

Can you find a positive whole number n such that both n and n+97 are perfect squares?

Translate into roots

Write:

n = a²,   n+97 = b²,   b>a

Subtract:

b² − a² = (b−a)(b+a) = 97

Because 97 is prime, its only positive factor pair is:

b−a = 1,   b+a = 97

Recover the roots

Add the equations
2b = 98 → b = 49
Subtract them
2a = 96 → a = 48
Recover n
n = 48² = 2304
Check: 2304 + 97 = 2401 = 49².

Checkpoint

Need a hint? Start here

Write the two squares as a² and b². Factor their difference as (b−a)(b+a).

b−a=1,b+a=97. Add or subtract to get b49,a48. 1;97;48;n=2304.

Mission 4

Explore every difference-of-squares case

The factor-pair method can produce one solution, several solutions, or no solution. This laboratory checks every factor pair, so no branch is missed.

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Predict first

Use the fresh gap 12 and factor pair 2×6. Predict the smaller root before using the laboratory.

Your prediction is checked with this mission. Try it before reading the worked steps below.

Recover whole-number roots. Count each pair of squares once, with the smaller square first. For a factor pair u×v=D with u≤v, set b=(v+u)/2 and a=(v−u)/2. The factors must both be odd or both be even; otherwise division by 2 gives half-integers. This laboratory allows a=0. The practice problem in Mission 3 requires a positive smaller square.

Difference-of-squares laboratory

Added pattern: a positive integer is a difference of two whole-number squares exactly when it is odd or divisible by 4. Numbers that leave remainder 2 when divided by 4 are impossible.

Checkpoint

Answer the printed gaps 24, 2, and 105; also fill the separate prediction for gap 12.

Need a hint? Start here

List factor pairs of the gap. Keep pairs with the same parity so both recovered roots are whole numbers.

Gap24 has pairs2×12 and4×6. Gap105 has1×105,3×35,5×21,7×15. Prediction2. Checkpoint:two;impossible;root1;four.

Mission 5

Shift a fixed number onto a square

A bounded addend creates a bounded square target. Search the roots of that target interval instead of testing every addend.

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Practice Question 7

Transfer problem

Add a two-digit prime to 2002 to obtain a perfect square. Find the prime.

Bound the target square

A two-digit prime is between 11 and 97, so the square must lie between:

2002+11 = 2013
2002+97 = 2099
44²1936too small
45²2025inside range
46²2116too large

Test a candidate addend

Checkpoint

Need a hint? Start here

Bound the target using the smallest and largest permitted addend; search only roots inside that interval.

2025−2002=23, and23 is prime. 2025;23;prime.

Mission 6

Count every allowed square shift

If B+x must be a square and L≤x≤U, then the square target lies in the shifted interval [B+L, B+U]. Root bounds count every solution at once.

Not complete
B + x = r²,   L ≤ x ≤ U
⌈√(B+L)⌉ ≤ r ≤ ⌊√(B+U)⌋

Here B, L, U and x are nonnegative whole numbers; both endpoints are included. The symbol ⌈√A⌉ means the smallest whole-number root whose square is at least A; ⌊√A⌋ means the largest whole-number root whose square is at most A. Every allowed root gives exactly one addend x=r²−B.

Shift-range laboratory

original connection: this lesson interval from 2024 through 2499 contains five squares. The same root-bound idea now works after shifting the entire interval.

Checkpoint

Use the printed three-digit and four-digit ranges below, even if you change the explorer.

Need a hint? Start here

Add the base to both endpoints, count the possible roots inclusively, then subtract the base from each square.

2010+[100,999]=[2110,3009], with roots46–54. 400+[1000,9999]=[1400,10399], with roots38–101. 46;54;nine;64.

Mission 7

Maximize a sum that must be square

An optimization proof needs an upper bound, the greatest square below that bound, and a construction that reaches it.

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Practice Question 9

Transfer problem

Three different two-digit numbers have a perfect-square sum. What is the greatest possible sum?

Bound first

The greatest possible sum of three different two-digit numbers is:

99+98+97=294

The greatest perfect square not exceeding 294 is:

17² = 289

Now we still need a construction that reaches 289.

Build an optimal triple

Enter three different whole numbers from 10 through 99 in any order. Your construction is checked along with the checkpoint below. Also count every unordered optimal triple: changing the order of the same three numbers does not create another triple.

Checkpoint and construction audit

Need a hint? Start here

Prove an upper bound, find the greatest square below it, then construct distinct numbers that attain it.

The greatest square at most294 is289. The five unordered constructions are92,98,99;93,97,99;94,96,99;94,97,98;95,96,98. 294;289;five. Enter any one construction in the three boxes.

Mission 8

Find the least square in a consecutive-number story

Use the middle number to compress three consecutive integers into one expression, then use the square condition.

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Practice Question 10

Transfer problem

Three consecutive four-digit positive integers have a perfect square as the middle number. Their sum is divisible by 15. Find the least possible middle number.

Compress the sum

Write the integers as:

n−1,   n,   n+1

Their sum is:

(n−1)+n+(n+1)=3n

For 3n to be divisible by 15, n must be divisible by 5. If n is a square divisible by 5, its root is divisible by 5.

Test square roots, not all four-digit numbers

Checkpoint

Find the least valid middle number in the original story, not just any valid slider example.

Need a hint? Start here

Use the middle number n: the total is 3n. Apply divisibility before searching the square roots.

All three integers must be four-digit. Roots start at32; the first divisible by5 is35. 35;1225;sum3675;yes.

Mission 9

Square-roots, gaps, and shifts workshop

Correct all eight answers to complete the workshop.

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Need a hint? Start here

Choose a method before calculating. Use the earlier local hint for that method, then verify the root, all stated conditions and the endpoints.

Count both endpoints in root intervals and count each square pair only once. 101;1980;2304;2;23;9;289;1225.

Mission 10

Exit ticket

Complete all ten missions, including all five exit questions, to earn the certificate.

Not complete

Fresh challenge: use the methods from this lesson on these new values. Check your calculations by squaring, listing a short cycle, or verifying every condition.

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Optional reflection — not automatically graded

20.5

Square-Root, Gap & Shift Navigator

This certifies that Student completed all ten missions and can work backward from perfect-square clues.

Chapter 20 • Perfect Squares

Need a hint? Start here

Choose a method before calculating. Use the earlier local hint for that method, then verify the root, all stated conditions and the endpoints.

Its roots are34–100:100−34+1=67. A square middle divisible by5 needs a root divisible by5. 161;no;67;93;next root40.