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Chapter 19 • Greatest Common Divisor & Least Common Multiple

Read GCD and LCM from Prime Exponents

从质因数指数中读出最大公约数与最小公倍数

Align the prime factorizations, fill missing primes with exponent zero, take the smallest exponent for the GCD, and the largest exponent for the LCM.

GCD keeps what every number shares. LCM collects what any number needs.
10 interactive missionsoriginal examples includedAutosaves in this browserEverything needed is on this page.
Work saves automatically.
Mission 1

Decide whether the story asks for a common divisor or a common multiple

Here all input numbers, divisors, and multiples are positive whole numbers. A divisor fits into a number with no remainder. A positive multiple is that number times 1, 2, 3, and so on. The words greatest and least positive tell us which common value to choose.

Not complete
÷
Greatest common divisor

The greatest positive integer that divides every given number.

gcd(a,b,c)

The worked example also writes this as (a,b,c).

×
Least common multiple

The least positive integer divisible by every given number.

lcm(a,b,c)

The worked example also writes this as [a,b,c].

Factor-and-multiple explorer

Run explorer

Checkpoint for the fixed numbers shown below

Need a hint? Start here

List shared factors for a greatest dividing unit; list shared multiples for a first repeat.

Check why it works

Shared divisors are 1,2,3,6; the first shared positive multiple is 36. GCD 6; LCM 36. A short displayed multiples list may end before the first common multiple.

Mission 2

Align every prime base—even when its exponent is zero

The worked example rewrites all three numbers with the same prime columns. A prime that is absent has exponent zero because p0=1.

Not complete
Try a smaller pair first: 12 = 2² × 3 and 18 = 2 × 3². Build the column for prime 2 before reading the larger table.

original numbers

2520 = 2³ × 3² × 5 × 7
14850 = 2 × 3³ × 5² × 11
819 = 3² × 7 × 13

Prime 2

Prime 11

Checkpoint for the fixed numbers shown below

Need a hint? Start here

A missing prime contributes no copies: its exponent is zero. Compare one column at a time.

Check why it works

Then use all three original numbers for the larger checkpoint; include zeros. Prediction: minimum 1, maximum 2. Checkpoint: exponent of 2 in 819 is 0; exponent of 11 in 2520 is 0; minimum exponent of 3 is 2; maximum exponent of 5 is 2.

Mission 3

Use the smallest exponents to find the worked example GCD

A prime can appear in the GCD only if every number contains it. The exponent cannot exceed the smallest exponent among the numbers.

Not complete

Minimum-exponent row

2⁰ × 3² × 5⁰ × 7⁰ × 11⁰ × 13⁰

Only the two copies of 3 survive in every number.

Why the other primes disappear

At least one original number has exponent 0 for each of 2, 5, 7, 11, and 13. The minimum exponent in each of those columns is therefore 0.

Increasing any minimum exponent would make the result fail to divide at least one number. This proves it is the greatest common divisor. Taking minimum exponents guarantees the result divides all three numbers.

Worked example 1 — GCD

Need a hint? Start here

A shared prime inventory cannot contain more copies than any one number supplies.

Check why it works

Only prime 3 has a positive minimum exponent, namely 2. Enter 3^2 (or 3² or 9) and numerical GCD 9. Any larger prime inventory would fail to divide at least one original number.

Mission 4

Use the largest exponents to find the worked example LCM

The LCM must contain enough copies of every prime to be divisible by each original number. That means taking the largest exponent in every column.

Not complete

Maximum-exponent row

2³ × 3³ × 5² × 7 × 11 × 13

Every original factorization can be made by removing prime copies from this complete inventory. Reducing any maximum exponent would leave too few copies for at least one original number. This proves the common multiple is the least positive one.

Multiply carefully

8 × 27 × 25 × 7 × 11 × 13
= 5,405,400
Each of 2,520, 14,850, and 819 divides this number exactly.

Worked example 1 — LCM

Need a hint? Start here

Collect enough copies of each prime to cover the largest requirement.

Check why it works

The required powers are 2³,3³,5²,7,11,13. Exponent of 3: 3; exponent of 5: 2; LCM 5405400. Reducing any required power would lose divisibility by a original number.

Mission 5

Complete the worked example guided practice

Apply the same aligned-table method to 35, 98, and 112.

Not complete

Guided Practice 1

35 = 5 × 7
98 = 2 × 7²
112 = 2⁴ × 7
Number257
35011
98102
112401
Minimum exponents001
Maximum exponents412

Enter both results

Need a hint? Start here

Insert zero for every missing prime before taking a minimum.

Check why it works

Minimum row 0,0,1; maximum row 4,1,2. GCD 7; LCM 2⁴×5×7²=3920.

Mission 6

Use a general prime-exponent laboratory

Enter two to six positive whole numbers. The page factors them, aligns every prime base, and builds the minimum and maximum exponent rows.

Not complete

The laboratory accepts 2–6 integers from 1 through 1,000,000,000. The number 1 has no prime factors; its prime-exponent row contains zeros. If every input is 1, there are no prime columns, and both the GCD and LCM are 1. Write numbers without thousands separators, since commas separate different inputs.

Analyze

Laboratory checkpoint

Answer for the fixed set 72, 90, and 120, even if you have explored another set in the lab.

Need a hint? Start here

Factor each input and align its prime columns. Check that the GCD divides each input.

Check why it works

Their minimum powers are 2×3; their maximum powers are 2³×3²×5. GCD 6; LCM 360.

Mission 7

Use exponent zero correctly when no prime is shared by all numbers

The chapter exercise gives a = 440, b = 126, and c = 825. Their prime columns overlap in pairs, but no prime appears in all three.

Not complete

440

2³ × 5 × 11

126

2 × 3² × 7

825

3 × 5² × 11
Pairwise overlap is not enough for the GCD of all three numbers. The minimum exponent in every prime column is 0, so the GCD is 1.

original Exercise 7 transfer

Need a hint? Start here

A prime shared by two numbers might still be absent from the third.

Check why it works

Every prime column has at least one zero. GCD 1; LCM 2³×3²×5²×7×11=138600.

Mission 8

Audit a new exponent table and catch common mistakes

A correct answer must use the minimum exponents for the GCD, maximum exponents for the LCM, and exponent zero for every missing prime.

Not complete

Transfer factorizations

A = 2⁴ × 3² × 5
B = 2² × 3⁵ × 7
C = 2³ × 3 × 5² × 7

Error 1

“Use the largest exponents for the GCD.”

Repair: the GCD must divide every number, so use the smallest exponents.

Error 2

“Ignore a prime when one number does not contain it.”

Repair: write exponent 0. That zero may remove the prime from the GCD.

Error 3

“Once I have a product, no verification is needed.”

Repair: check that the GCD divides every number and every number divides the LCM.

Transfer checkpoint

Need a hint? Start here

Calculate the minimum and maximum separately for each prime column.

Check why it works

Minimum powers 2²×3; maximum powers 2⁴×3⁵×5²×7. GCD 12; LCM 680400.

Mission 9

Independent workshop

Correct all eight questions to complete the workshop.

Not complete

1. gcd(18,30)

2. lcm(18,30)

3. gcd(35,98,112)

4. lcm(35,98,112)

5. If prime 13 is absent from a number’s factorization, its exponent in the aligned table is …

6. gcd(2520,14850,819)

7. lcm(2520,14850,819)

8. lcm(440,126,825)

— / 8
Need a hint? Start here

Choose the method before calculating. Revisit the local hint for that method, then verify every condition in the question.

Check why it works

Include zeros wherever a prime is absent. Answers: 6; 90; 7; 3920; 0; 9; 5405400; 138600.

Mission 10

Objective exit ticket

Complete all ten missions, including 5 out of 5 on this ticket, to earn the certificate.

Not complete

1. The GCD uses which exponents?

2. The LCM uses which exponents?

3. gcd(48,60,90)

4. lcm(48,60,90)

5. A missing prime has exponent …

— / 5
G/L

Prime-Exponent GCD & LCM Architect

This certifies that the student can align prime factorizations, use zero exponents, and read both GCD and LCM from exponent columns.

Lesson 19.1 • Chapter 19

Optional reflection — not automatically graded

Need a hint? Start here

Choose the method before calculating. Revisit the local hint for that method, then verify every condition in the question.

Check why it works

Minimum powers 2×3; maximum powers 2⁴×3²×5. Smallest; largest; 6; 720; 0.