18.4Math Education · Prime Factorization
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Grade 5 · Chapter 18 · Lesson 4

Arrange Prime Factors to Fit Digit Patterns

把质因数重新组合,满足数位与数字条件

In digit patterns, abc means the three-digit number 100a + 10b + c, not a × b × c. AB and CD likewise name two-digit numbers. Prime factorization creates a complete pool of possible factors. Digit length, distinct-letter rules, repeated blocks, leading-zero rules, and consecutive-prime conditions decide which arrangements actually fit.

Generate with factors. Filter with digits. Verify every condition.
10 missionsFactor-pair laboratoriesRepeated-block algebraoriginal Examples 2 and 4 · Guided Practices 2 and 4
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Mission 1

Let factorization generate candidates; let digit conditions filter them

A correct product is only the first gate. A candidate must also satisfy every place-value and digit rule in the statement.

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1Factor the targetList every possible factor pair or grouping.
2Apply digit lengthsOne factor may need one, two, or three digits.
3Apply digit rulesReject leading zero and repeated letters when letters must differ.
4Multiply backVerify the product and every stated pattern.

Digit length

100 ≤ abc ≤ 999

A three-digit factor cannot be replaced by a two- or four-digit factor.

Different letters

abcd

Different letters represent different digits when the question explicitly requires this.

Leading zero

037 is not a three-digit number

A first digit cannot be zero unless a fixed-width code is explicitly allowed.

Strategy check

Need a hint? Start here

Digit length puts bounds on each factor.

How can I check my reasoning?

Count positions a,b,c,d, then check lengths and the stated digit rule. Four positions; no leading zero; no, a correct product alone is insufficient.

Mission 2

Worked example 2 — solve abc × d = 1,995

Different letters represent different digits. The three-digit factor and the one-digit factor must use four different digits altogether.

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Example 2

Start with the prime inventory

1,995 = 3 × 5 × 7 × 19

The worked example regroups these prime factors into a three-digit number and a one-digit number.

Enter the unique valid expression

Need a hint? Start here

Try each possible one-digit divisor and check the quotient.

How can I check my reasoning?

d=1 gives a four-digit quotient; 3 and 5 give repeated digits. Only 285×7=1995 uses four different digits. Answers: 285; 7; 1995.

Mission 3

Use a complete three-digit × one-digit candidate laboratory

Testing only the first promising factor is not a proof. This laboratory checks every one-digit divisor from 1 through 9.

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Three-digit × one-digit solver

Classify the worked example search

Need a hint? Start here

Check that all four digits differ after finding an exact product.

How can I check my reasoning?

Check all divisors 1 through 9, including unsuccessful cases. One valid arrangement: 285×7. The result is unique.

Mission 4

Guided Practice 2 — fit 1,995 into two two-digit factors

In AB × CD = 1,995, the four letters represent four different digits. Generate all factor pairs first; then apply the two-digit and distinct-digit filters.

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Guided Practice 2

Why one pair survives

Both factors must lie from 10 through 99. Then all four written digits must occur exactly once.

Order does not change the requested sum

21 × 95 and 95 × 21 use the same four digits. The worked example asks for their sum, so factor order is irrelevant.

Enter either factor order

Need a hint? Start here

Test both two-digit factors and inspect their digits.

How can I check my reasoning?

The two-digit pairs are 21×95 and 35×57; the second repeats 5. Enter 21 and 95 in either order. The digit sum is 2+1+9+5=17.

Mission 5

Translate a repeated digit block into multiplication

Treat the first three digits as one number and the final four digits as another. If the latter is ten times the former, the seven-digit number has a rigid form. In Missions 5–7, digits within the block may repeat: abc does not require a, b and c to differ.

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Block form

123
123
0
1,231,230

Place-value identity

abcabc0 = abc × 1001 × 10
1001 = 7 × 11 × 13

Writing the three-digit block twice gives 1000 × block + block. This creates 1001 copies of the block; appending zero multiplies by 10.

Repeated-block explorer

Block123
Last four digits1230
10 × block1230
Pattern passes?Yes

Complete the place-value check

Need a hint? Start here

abcabc0 is the block times (10,000 + 10).

How can I check my reasoning?

The multiplier is 10010=10×1001, and 1001=7×11×13. 10010; 13; 1231230. Repeated digits within abc are allowed.

Mission 6

Worked example 4 — recover the seven-digit phone number

The phone number is the product of eight consecutive primes, and its final four digits are ten times its first three digits.

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Example 4

Why the consecutive-prime window is forced

The number ends in 0, so its prime product contains both 2 and 5. A consecutive-prime list containing both must begin:

abcabc0 = abc × 2 × 5 × 7 × 11 × 13

The five fixed prime factors already appear in the eight-prime product. The three remaining primes determine abc.

fixed: 2fixed: 5fixed: 7fixed: 11fixed: 13remaining: 3remaining: 17remaining: 19

Recover the block

abc = 3 × 17 × 19 = 969

Verify the complete number

969 × 10010 = 9,699,690

The final four digits are 9,690, exactly ten times 969.

Enter the worked example result

Need a hint? Start here

Divide out the fixed factors in 10,010, then match the remaining primes.

How can I check my reasoning?

The product includes 2, so its eight-prime window starts at 2 and ends at 19. After removing 2×5×7×11×13, the block is 3×17×19=969. Number: 9699690; largest prime: 19.

Mission 7

Guided Practice 4 — enumerate before claiming uniqueness

Find every seven-digit number meeting the conditions below. Use a complete consecutive-prime search to decide whether the answer is unique.

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Why is this search complete? A seven-digit number is at most 9,999,999. Moving a consecutive-prime window forward replaces each prime by a larger prime, so its product increases. Stop at the first product above 9,999,999: every later window is too large. The table includes that stopping row.
Guided Practice 4

A seven-digit number has the form abcabc0 and equals four times the product of six consecutive primes.

Clarification: the printed prompt uses singular wording. The complete search yields two valid seven-digit numbers. This lesson accepts both and does not silently discard either one.

State what the complete search proves

Need a hint? Start here

Check every consecutive-prime window until the product is too large.

How can I check my reasoning?

Stop once that result exceeds 9999999; later windows are larger. The two passing values are 1021020 and 6466460. Both have form abcabc0, so the answer is multiple.

Mission 8

Use a general factor-pattern studio

Digit length is itself a pattern. This transfer asks for two two-digit factors of 3,927, then lets you explore any product and digit-length combination.

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18 · Question 1

Transfer problem

Two two-digit numbers have product 3,927. Find their sum.

AB × CD = 3,927

Factor-pair pattern solver

With equal digit lengths, a pair and its reversal count once. With different lengths, the first and second factor must match their respective lengths. Repeated digits are allowed in the 3,927 transfer, including the two 7s in a factor.

Complete the transfer

Need a hint? Start here

Use factor pairs, then check digit lengths and the requested sum.

How can I check my reasoning?

3927=3×7×11×17. Generate factor pairs and keep two-digit factors. 51×77=3927. Smaller 51; larger 77; sum 128.

Mission 9

Digit-pattern and factor-arrangement workshop

Correct all eight responses to complete the workshop.

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Need a hint? Start here

Choose the strategy first: factor, apply the conditions, and multiply back. Revisit the relevant local hint above.

How can I check my reasoning?

Use the exact digit condition specified in each earlier problem. Answers: 4; 285; 7; 17; 10010; 969; 2; 128.

Mission 10

Objective exit ticket

Complete all ten missions, including 5 out of 5 on this exit ticket, to earn the certificate.

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Chapter 18 Achievement

Prime-Factor Digit-Pattern Architect

This certifies that

Grade 5 Mathematician

can generate factor candidates, apply digit-length and distinct-digit constraints, translate repeated blocks into multiplication, search consecutive-prime windows, and identify non-unique original conditions.

Need a hint? Start here

Work without the laboratories first. Explain which prime copies or factor pairs your answer uses, then verify the result.

How can I check my reasoning?

For 1728, the valid distinct-digit products are 864×2, 576×3 and 432×4. Answers: 13; 2342340; 21; 143; 3.

Teaching notes