15.4Grade 5 Math Lab
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Chapter 15 · Divisibility and place value

Work Backward after Inserting a Decimal Point

Lesson 15.4 · 添上小数点后倒推原数

A decimal point keeps the digits in the same order but changes their values. Use the amount lost, the point position, exact whole-number checks, and column subtraction to recover the original four-digit number.

Locate the point. Build the equation. Verify the original number.
10 missionsTwo complete original problemsForward and reverse solverEverything needed is on this page.
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Mission 1

See exactly what the decimal point changes

Every original number in this lesson is a whole number from 1000 to 9999. Imagine its decimal point at the right end first: 2004 means 2004.0. Inserting a point moves it left by 1, 2, 3, or 4 places without reordering the four original digits.

Not complete

Four possible positions

Let N be a four-digit whole number. Placing the point before a digit gives:

abc.d = N÷10ab.cd = N÷100a.bcd = N÷10000.abcd = N÷10000

The practice problem says the point is inserted before one of the digits. We will test every mathematically possible position rather than assume one.

The lost amount

If the point moves k places left, the new number is:

new = N ÷ 10k

The absolute difference is:

D = N − N÷10k

Decimal-point explorer

Original
After inserting the point
Division factor10
New value200.4
Absolute difference1803.6
Digits reordered?No

Check the place-value model

Mission 2

Audit every point position in the practice problem

This worked example asks for a four-digit number whose value becomes 1,803.6 smaller after a decimal point is inserted.

Not complete
Worked example 5

Complete problem

A decimal point is inserted before one digit of a four-digit whole number. The absolute difference between the original number and the new decimal is 1,803.6. Find the original four-digit number.

Do not guess the point position

For each possible shift k, solve:

N = D×10k ÷ (10k−1)

Keep a candidate only when it is a four-digit whole number.

What counts as a valid branch?

The candidate is a whole numberrequired
The candidate lies from 1000 to 9999required
Reinserting the point reproduces 1803.6required

Exact position audit

ShiftPoint positionCandidate from the equation (≈ means rounded display)Four-digit whole?Verification
Run the audit to test every position before checking this mission. Exact fractions determine whether a candidate is whole; a rounded display does not.
Mission 3

Solve the practice problem with an equation

The position audit shows that the decimal point was placed before the final digit, so the new value is one tenth of the original.

Not complete
N − N÷10 = 1803.6translate the story
10N − N = 18036multiply by 10
9N = 18036combine like terms
N = 2004divide by 9

Verification

2004 − 200.4 = 1803.6

The digits remain 2, 0, 0, 4 in the same order.

Instructional note

The next mission develops the worked example’s own digit-by-digit method.

Mission 4

Reconstruct the digits with the worked example’s column method

Align the decimal points. The new decimal is abc.d while the original is abcd.0.

Not complete

Aligned subtraction

Borrowed top values, from thousands to tenths: 1 · 10 · 0 · 3 · 10. The hundreds receive 10 from the thousands; the tenths receive 10 from the ones.

Scroll the subtraction sideways on a small screen to keep each place-value heading aligned.

thousands
hundreds
tens
ones
tenths
2
0
0
4
.
0
0
2
0
0
.
4
1
8
0
3
.
6

Let the original digits be a, b, c, d

abcd.0 − abc.d = 1803.6

Start at the tenths column and move left. Every borrow creates the next digit condition.

1

Tenths: borrow one whole, so 10−d=6. Therefore d=4.

2

Ones: after the borrow, (d−1)−c=3. With d=4, we get c=0.

3

Tens: the difference digit is 0, so c−b=0. With c=0, we get b=0.

4

Hundreds: borrow from the thousands place: 10+b−a=8. With b=0, we get a=2.

5

Final check: the thousands column is a−1=1, which agrees with a=2. The original is 2004.

Mission 5

Complete the worked example guided practice

A four-digit number becomes 2,003.4 smaller after a decimal point is inserted. First run the four-position search below: only shift 1 survives. The displayed equation then recovers that original number.

Not complete
Guided Practice 4
N−N÷10=2003.4point before final digit
10N−N=20034clear the decimal
9N=20034combine
N=2226divide by 9

Test a candidate

Candidate
Point before final digit
Calculated difference1800
Target2003.4
Matches?No
Whole four-digit?Yes
Mission 6

Use a forward and reverse decimal-point laboratory

Generate a difference from a known original, then reverse the process by auditing every possible point position. For this mission’s fixed questions, run the reverse solver on 4277.79, regardless of any other examples you explore.

Not complete

Forward generator

New decimal43.21
Difference D4277.79
Factor100
EquationN−N/100

Reverse solver

ClassificationNot searched
Mission 7

Decide whether the answer is unique, multiple, or impossible

A difference alone does not always identify exactly one original number. A complete position audit tells us what the evidence proves.

Not complete

Unique

D=1803.6

Only one point position produces a four-digit whole number.

Multiple

D=990

Both 1100−110.0 and 1000−10.00 equal 990.

Impossible

D=1803.5

No point position produces a valid four-digit whole number.

Complete case audit

1803.6

Not audited

990

Not audited

1803.5

Not audited

Mission 8

Verify a claim and transfer the method

A recovered number is not finished until the point is reinserted and the subtraction exactly reproduces the stated difference.

Not complete

Verification checker

Shifted number48.00
Actual difference4752
Claimed difference4752
Exact match?Yes

Transfer A

The point is inserted before the final digit, and the number becomes 3,888.9 smaller.

9N = 38889

Transfer B

The point moves two places left, and the number becomes 4,752 smaller.

99N = 475200
Mission 9

Decimal-point reverse-engineering workshop

Correct all eight answers to complete this workshop.

Not complete
Worked explanation for question 1

Each move divides by 10; three moves divide by 1000.

Worked explanation for question 2

Keep digit order and divide by 100.

Worked explanation for question 3

3456 − 34.56 = 3421.44.

Worked explanation for question 4

9N = 11106, so N=1234.

Worked explanation for question 5

99N = 247500, so N=2500.

Worked explanation for question 6

1000 groups minus one group leaves 999 groups.

Worked explanation for question 7

2200−220=1980 and 2000−20=1980; shifts 3 and 4 give nonintegers.

Worked explanation for question 8

6789÷1000=6.789.

Workshop score0 / 8
Mission 10

Objective exit ticket

Complete all ten missions, including a perfect exit score, to earn the certificate.

Not complete
Worked explanation for question 1

9N=51003, so N=5667.

Worked explanation for question 2

99N=534600, so N=5400.

Worked explanation for question 3

2500−2.5=2497.5.

Worked explanation for question 4

Shift 1 gives 1000. Other shifts give values below 1000.

Worked explanation for question 5

Divide by 100 and retain all four digits.

Exit score0 / 5

Certificate of mathematical thinking

Decimal-Point Reverse Engineer

Grade 5 Mathematician

has completed Lesson 15.4 by locating decimal-point positions, recovering original numbers, and verifying every solution exactly.

Optional reflection

Why is verification especially important here?

Explain why finding a whole-number candidate is not enough until the decimal point is reinserted in the claimed position.

Learning notes

About this lesson

The worked example uses digit-by-digit column subtraction to recover 2004. This lesson preserves that method in Mission 4 and adds a position audit, an equation route, a general forward/reverse solver, uniqueness classification, transfer problems, workshop, and exit ticket as instructional scaffolds.