12.2Grade 5 Math Lab
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Chapter 12 · Periodic Problems

Repeating Decimals:
Nth Digit and Digit Sum

Lesson 12.2 · 循环小数中的远位数字与数字和

Discover a decimal cycle through long division, jump to a far-away digit with a remainder, and total thousands of digits without writing them all.

One repeating block can answer two different questions.

Grade 510 missionsSelf-containedInteractive long division
Mission 1

Read a repeating decimal precisely

A bar over digits means that the entire marked block repeats forever. The period is the number of digits in the smallest repeating block.

Not complete
Example 1
27 = 0.285714

The digits after the decimal point are:

Three details to keep separate

Repeating block: 285714

Period: 6 digits

Position: the first digit after the decimal point is position 1.

Your turn

Position check: positions 1–6 form the first cycle; positions 7–12 form the second cycle. Position 8 is therefore the second digit of the block.
Mission 2

Watch long division create the cycle

A decimal digit is determined by the current remainder. Once the same remainder returns, the same future digits must repeat.

Not complete

Remainder machine for 2 ÷ 7

At each step: multiply the remainder by 10, choose the next digit, and record the new remainder.

StepStart remainderRemainder × 10Next digitNew remainder
Press “Next step” to begin.

Remainders around the loop

The first remainder is 2. Follow it until 2 returns.

same remainder → same next digit → same future
Mission 3

Find the 2,014th digit

Use the period to replace a huge position with one small position inside the repeating block.

Not complete
2014 = 335 × 6 + 4
285714
× 335+
2857

Interpret the division

335 complete six-digit cycles come first.

The remainder 4 means the target lands on the fourth digit of 285714.

Record the result

Mission 4

Find the sum of the first 2,014 digits

For a digit sum, add the values of the individual digits, not the decimal numbers. Every complete cycle contributes the same cycle sum. The “leftover-prefix sum” means the sum of the first r digits of the repeating block.

Not complete
digit sum = complete cycles × cycle sum + leftover-prefix sum
335 complete cycles335 × 27because 2+8+5+7+1+4 = 27
+
first 4 leftover digits2+8+5+7prefix sum = 22
=
first 2,014 digits9,067total digit sum
Do not multiply 2,014 by 27. Twenty-seven is the sum of six digits, not the sum contributed by one position.
Mission 5

Keep a leading zero inside the cycle

A zero immediately after the decimal point is still a digit and still occupies a position.

Not complete
Guided Practice 1
113 = 0.076923

Long-division remainder chain

1 → 10 → 9 → 12 → 3 → 4 → 1

The first step produces digit 0 because 10 is smaller than 13. When remainder 1 returns, the six-digit block begins again.

Use the same 2,014 = 335×6+4 split

The fourth digit in 076923 is 9.

One block still sums to:

0+7+6+9+2+3 = 27

The first four digits still sum to 22, so the total is again 9,067.

Mission 6

Compare the two original examples

Two decimals can have different blocks and different distant digits while sharing the same period and the same total digit sum.

Not complete
FractionRepeating blockPeriodCycle sum2,014th digitFirst 2,014 digit sum
2/728571462779,067
1/1307692362799,067
Mission 7

Use a repeating-decimal laboratory

Enter digits that repeat starting at decimal position 1 and a whole-number target position from 1 to 1,000,000,000. The laboratory reduces repeated copies to the shortest block before calculating. For example, entering 4545 uses block 45 and period 2. This lab does not include a nonrepeating prefix.

Not complete
Digits only; a leading zero is allowed.
6period p
335complete cycles q
4remainder r
7Nth digit
27cycle sum
22leftover-prefix sum
9067first N digit sum
4block position
2014 = 335 × 6 + 4

The fourth digit is highlighted.

Record two laboratory challenges

A. Block 36, N = 100

B. Block 142857, N = 2,025

Mission 8

Repeating-decimal error detective

Judge each statement. Pay special attention to leading zeros, the meaning of the remainder, and the difference between one digit and a digit sum.

Not complete

1. In 0.076923, the first digit after the decimal point is 0.

2. Because 2014 ÷ 6 has remainder 4, the 2,014th digit of 0.285714 is 4.

3. To sum the first N digits, multiply N by the sum of one complete block.

4. If r = 0, the leftover-prefix sum is 0 and the Nth digit is the final digit of the block.

5. A repeating block may begin with 0; that zero still counts toward the period.

When long division stops — and when it repeats

For 1 ÷ 4: 10 ÷ 4 gives digit 2, remainder 2; 20 ÷ 4 gives digit 5, remainder 0. The decimal ends: 0.25. A zero remainder in the long-division calculation means the decimal terminates. This differs from a zero remainder when dividing a digit position by a block length, which locates the last digit of a block. A repeated nonzero long-division remainder starts the same future digits again.

original Exercise 1: a decimal with a warm-up

Find digit 2,016 of 3/35 and the sum of the first 2,016 digits. Long division begins with digit 0, remainder 30. Then the remainders are 30 → 20 → 25 → 5 → 15 → 10 → 30, producing digits 8,5,7,1,4,2.

Thus 3/35 = 0.0857142. The first zero is a nonrepeating prefix. The six-digit cycle starts at decimal position 2.

Hint: separate the prefix

Remove the first digit before dividing the remaining number of positions by six. For the sum, include the prefix's contribution too.

Worked solution

2,016 − 1 = 2,015 = 335 × 6 + 5. Read the fifth digit of 857142: 4. Each full block sums to 27; the first five digits sum to 25. Total = 0 + 335 × 27 + 25 = 9,070.

original Exercise 2: choose where to start on a digit ring

Read this ring clockwise forever: 8 → 3 → 4 → 3 → 9 → 8 → 9 → 7 → 3 → 9 → back to 8. Choose one digit for the integer part, put the decimal point immediately after it, and keep reading clockwise. Which starting point gives the greatest number? Which gives the least?

The order cannot be rearranged. A ring diagram is not needed to infer any extra dimensions: the arrows give the complete order.

Hint: compare from left to right

The greatest integer part must be 9, and the least must be 3. If two candidates share their integer part, compare decimal digits until they differ.

Worked solution

The largest starts at the fifth ring position, the 9 immediately after 4,3 and begins 9.8973983439…. The smallest starts at the second ring position, the 3 immediately before 4 and begins 3.4398973983…. The ten digits after each decimal point form its repeating block.

Mission 9

Independent workshop

Try each new problem before opening a hint. Correct all 8 answers to complete this mission.

Not complete
Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

32 = 10 × 3 + 2. The target is block position 2, digit 4.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

32 = 10 × 3 + 2. Block sum 11; leftover sum 4. Total = 10 × 11 + 4 = 114.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

81 = 40 × 2 + 1. The target is block position 1, digit 2.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

81 = 40 × 2 + 1. Block sum 7; leftover sum 2. Total = 40 × 7 + 2 = 282.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

108 = 27 × 4 + 0. The target is block position 4, digit 4.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

108 = 27 × 4 + 0. Block sum 10; leftover sum 0. Total = 27 × 10 + 0 = 270.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

20 = 3 × 6 + 2. The target is block position 2, digit 7.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

20 = 3 × 6 + 2. Block sum 27; leftover sum 7. Total = 3 × 27 + 7 = 88.

Mission 10

Transfer exit ticket

Try each new problem before opening a hint. Correct all 5 answers to complete this mission.

Not complete
Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

74 = 24 × 3 + 2. The target is block position 2, digit 3.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

74 = 24 × 3 + 2. Block sum 11; leftover sum 3. Total = 24 × 11 + 3 = 267.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

52 = 13 × 4 + 0. The target is block position 4, digit 2.

Hint

Keep any leading zero. Split into complete blocks and leftover digits.

Worked explanation

52 = 13 × 4 + 0. Block sum 13; leftover sum 0. Total = 13 × 13 + 0 = 169.

Hint

Can the entered block be made from copies of something shorter?

Worked explanation

4545 consists of two copies of 45. The smallest period is 2.

Optional reflection — not automatically graded

Lesson checkpoints completed

Repeating-Decimal Cycle Navigator

This certifies that the learner can discover a decimal cycle, locate a distant digit, preserve a leading zero, and sum many decimal digits by complete cycles and a leftover prefix.

Lesson 12.2 · Grade 5 Periodic Problems

Teaching notes

The long-division stepper, comparison table, general repeating-block laboratory, additional blocks 36 and 142857, feedback, workshop, and exit ticket are added self-contained teaching scaffolds.