11.6Math Adventure · Logical Reasoning II
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Chapter 11 · Logical Reasoning II

Lesson 11.6 — Enumerate Cases and Test Feasibility

枚举情况与检验可行性

A strong case list is not random guessing. It defines every candidate, applies every clue, records every rejection, and proves what is possible, impossible, unique, or greatest.

Define → enumerate → filter → construct → verify.
Grade 5Self-containedFive investigationsObjective checks
Mission 1

Build a complete candidate ledger

Enumeration becomes proof only when the candidate set is complete and every survivor is checked against every condition.

Not complete

The five-step habit

  1. Define the full candidate set.
  2. Apply the strongest clue first.
  3. Record why each candidate survives or fails.
  4. Construct an example when possibility or a maximum must be proved.
  5. Audit every original condition.
Important: finding one failed guess does not prove all other guesses work. Finding one successful guess does not prove it is unique or greatest.

Warm-up candidate set

Select every integer from 1 through 12 that is even and not divisible by 3.

Selected: 0 candidates

CandidateEven?Divisible by 3?Survives both clues?
Mission 2

Use every number card exactly once

This practice problem turns arithmetic clues into candidate pairs, then removes assignments that reuse a card.

Not complete

Number-card puzzle

There is exactly one card for each whole number 1 through 9. Order within a two-card pair does not matter. Players A, B, C, and D each take two cards.

  • A's two cards have sum 10.
  • B's larger card minus the smaller card equals 1.
  • C's two cards have product 24.
  • The larger of D's two cards divided by the smaller equals 3.

Every card is used at most once. Which card remains?

Enumerate clue-specific pairs

A · sum 10:
B · difference 1:
C · product 24:
D · quotient 3:

Choose one pair for each player

Choose four pairs. Reused cards will be flagged.
Mission 3

Find an upper bound in the rotating-player game

A maximum needs a limit. Here the key limit is that a resting player must enter the next match and therefore cannot rest twice in a row.

Not complete

Table-tennis rotation

A, B, and C play table tennis. Each match uses two players. Every match has a winner and a loser. The winner stays, and the loser is replaced by the resting third player in the next match. When A has played 9 matches and B has played 6 matches, what is the greatest possible number of matches C could have played?

9C appearances
3A rests
6B rests
3C rests

Appearances: 9 + 6 + C = 2 × matches

Testing…

Why rest counts matter

In every match exactly one player rests. If a player rests now, that player enters the next match. Therefore no player's rest marks may be adjacent.

Maximum rests in M matches = ⌈M ÷ 2⌉ (divide by 2, then round up to a whole number)

For each tested total, compare A's, B's, and C's required rest counts with that maximum.

Upper-bound strategy: Each game involving C also includes A or B, so C cannot exceed their 9 + 6 = 15 combined appearances. Hence the total number of matches is at most (9 + 6 + 15) ÷ 2 = 15. Now find the largest total of matches whose required rest counts could still be arranged without consecutive rests.
Total matches MC appearancesA restsB restsC restsMax rests for one playerFeasible?
Mission 4

Construct the maximum case

An upper bound is not enough. We must exhibit an actual match schedule that reaches it.

Not complete

A 13-match rest schedule

The row records who rests in each match. Adjacent resters are different, so the schedule can occur: the next rester is the current match's loser.

0A appearances
0B appearances
0C appearances
Repeated adjacent rests?
Mission 5

Enumerate periodic alignments

Two repeating reports create a 12-position combined cycle, but the second report's alignment depends on the line length.

Not complete

Soldiers reporting from opposite ends

Soldiers stand in one line. First they report from left to right using the repeating pattern 1, 2, 3, 4, with the leftmost soldier starting at 1. Then they report from right to left using the repeating pattern 1, 2, 3, 4, 5, 6, with the rightmost soldier starting at 1. Exactly five soldiers report 3 both times. What is the greatest possible number of soldiers?

0Both reports are 3
4Left cycle
6Right cycle
12Combined cycle

Matching positions: —

Systematic scan

Why 12 positions, and why can the scan stop?

At position i from the left, the first report is 3 when i = 3, 7, 11, … . The second report is 3 when N − i leaves remainder 2 on division by 6. Both conditions repeat after 12 positions because 12 is divisible by both 4 and 6.

If N is even, the required positions have different parities and cannot meet. For odd N, this table identifies the first double-3 position; add 12 repeatedly.

Remainder of N ÷ 12First matching positionFirst N in this class with at least six matches
11173
3775
5365
71179
9769
11371

Within each remainder class, increasing N by 12 adds one matching position. Every odd N above 67 is therefore already at or beyond that class’s six-match threshold. The only five-match lengths are 53, 57, 59, 61, 63, and 67.

If the line length is even, the two kinds of “3” fall on opposite parities, so there are no double-3 reporters. For an odd length, double-3 reporters repeat every 12 positions.

Candidate lengths will appear here.

Scanning through 80 is enough: every odd length greater than 67 already contains a sixth double-3 position, while every even length contains none. Thus no later length can return to exactly five.

Mission 6

Enumerate distinct shooting-score sets

The score total and best-shot limit reduce a large-looking problem to four candidate sets.

Not complete

Shooting practice

A, B, and C each fire four shots, and every shot hits. Each shot scores a positive whole number from 1 through 7 rings. Each person's four scores are different and total 17. B has exactly two score values in common with A. A and C have exactly one score value in common. What is that common score?

Step 1 · Generate every four-number set

Choose four distinct positive integers from 1 through 7 whose sum is 17. Order does not matter.

Step 2 · Test an assignment

Choose three candidate sets.

Step 3 · Look for an invariant

More than one full assignment survives. The question is still answerable because the one score shared by A and C is the same in every valid assignment.

0Valid ordered assignments
?Shared A–C score in all cases
0Candidate score sets
17Each person's total
Mission 7

List possible and impossible scores

A score is feasible exactly when it can be written as 6 × wins + 5 × draws. Losses add zero and do not change the score.

Not complete

Game-score problem

Each round gives 6 points for a win, 5 for a draw, and 0 for a loss. The number of rounds is unrestricted. How many positive whole-number scores can never be obtained?

Choose a score

Click a score to see whether a nonnegative combination of 6-point wins and 5-point draws exists.

Score = 6w + 5d

Why the search can stop

The five consecutive scores 20, 21, 22, 23, and 24 are all attainable:

20 = 4×5 · 21 = 3×5+1×6 · 22 = 2×5+2×6 · 23 = 1×5+3×6 · 24 = 4×6

Adding another 5-point draw produces the next block of five scores. Therefore every score at least 20 is attainable.

Mission 8

Name exactly what the evidence proves

Different case analyses establish different conclusions. Do not overclaim.

Not complete
Card puzzle: after all pair choices and no-reuse checks, one full assignment survives.
Table tennis: Any C count above 11 is impossible: even counts make 9+6+C odd, while odd counts 13 or 15 require too many B rests; C cannot exceed 15. A construction reaches 11.
Soldier line: several lengths produce five double-3 reports. Is the line length uniquely determined by the clues? Classify the set of possible lengths, rather than the maximum value.
Shooting: several A–B–C set assignments survive, but the A–C common score is unchanged.
Game score 19: no nonnegative whole numbers w and d satisfy 6w+5d=19.
Mission 9

Independent workshop

Solve at least 6 of 8 fresh problems. Each has a local hint.

Not complete
Hint

List multiples of three, then remove the even ones.

Hint

List smaller card first so no pair is counted twice.

Hint

Try each possible number of seven-point rounds.

Hint

Find four consecutive attainable totals. Explain why adding another four-point round then covers every larger total.

Hint

Compare with the largest possible four-number sum.

Hint

A player participates whenever they are not resting.

Hint

The resting person must enter the next match.

Hint

Distinguish a fixed requested value from a unique full case.

Mission 10

Independent exit ticket

Solve all five fresh problems. The certificate also requires Missions 1–9.

Not complete
Hint

List every multiple of four in the range, then filter.

Hint

Start with the smallest possible smaller card.

Hint

Test small totals and find three consecutive attainable ones.

Hint

A consecutive block must cover every remainder when adding three.

Hint

Count the matches in which C is not the resting player.

Optional reflection — not automatically graded

Certificate of mastery

Case Enumeration & Feasibility Architect

This certifies that the learner can define complete candidate sets, eliminate impossible cases, construct attainable extremes, use periodicity, and state exactly what a case analysis proves.

Lesson 11.6 · Grade 5 Mathematical Reasoning

Teaching notes

The warm-up ledger, exhaustive-search displays, explicit constructions, general labels, workshop, and exit ticket are added instructional scaffolds.